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问 15道递等式计算带答案

2025-06-28 01:44:35
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在数学学习中,递等式计算是一种常见的练习方式,它有助于培养学生的逻辑思维和运算能力。递等式也被称为分步计算,即按照运算顺序逐步完成每一步的计算,并最终得出结果。以下是一些典型的递等式题目及对应的解答,适合小学高年级或初中阶段的学生练习。

1. 24 + 36 ÷ 6 × 2

= 24 + 6 × 2

= 24 + 12

= 36

2. (18 - 9) × (7 + 3)

= 9 × 10

= 90

3. 120 ÷ (10 - 4) + 5

= 120 ÷ 6 + 5

= 20 + 5

= 25

4. 7 × (8 + 2) - 30

= 7 × 10 - 30

= 70 - 30

= 40

5. (5 + 3) × 4 - 12

= 8 × 4 - 12

= 32 - 12

= 20

6. (15 - 5) ÷ 5 + 10

= 10 ÷ 5 + 10

= 2 + 10

= 12

7. 6 × 4 + 20 ÷ 5

= 24 + 4

= 28

8. (9 + 6) × 2 - 10

= 15 × 2 - 10

= 30 - 10

= 20

9. 30 - (12 ÷ 4) × 3

= 30 - 3 × 3

= 30 - 9

= 21

10. (10 + 5) × 2 ÷ 3

= 15 × 2 ÷ 3

= 30 ÷ 3

= 10

11. 8 × (6 - 2) + 10

= 8 × 4 + 10

= 32 + 10

= 42

12. (16 ÷ 4) + (5 × 3)

= 4 + 15

= 19

13. 25 - (10 + 5) ÷ 3

= 25 - 15 ÷ 3

= 25 - 5

= 20

14. (7 + 3) × (9 - 5)

= 10 × 4

= 40

15. 18 ÷ (6 ÷ 3) + 4

= 18 ÷ 2 + 4

= 9 + 4

= 13

通过这些递等式题目的练习,学生可以更好地理解运算顺序、括号的作用以及如何一步步进行复杂计算。建议在做题时先理清运算顺序,再逐步拆解,确保每一步都准确无误。希望以上内容对大家的学习有所帮助!